![]() ![]() ![]() † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4. ![]() The truth is that it is not, hence the survival tips mentioned at the beginning of this section. Next to the lake, a glacier with the same volume as the floating ice sits on land. This is counter-intuitive as most assume that the door would be relatively easy to open. Why is a force exerted by a static fluid on a surface always perpendicular to the surface Imagine that in a remote location near the North Pole, a chunk of ice floats in a lake. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Find the fluid force (in lb) on a circular end of the tank when the. Note that the volume of the cylinder (and that of the fluid it displaces) equals (h 2 h 1)A. You may assume that the buoyant force is F 2 F 1 and that the ends of the cylinder have equal areas A. 3 ¯, - 2.25 ) ( 0, - 2.25 ) ( 0, 0 ) y y x Figure 6.5.7: Sketching a submerged car door in Example 6.5.3. A cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. Referring to Figure 14.20, prove that the buoyant force on the cylinder is equal to the weight of the fluid displaced (Archimedes’ principle). Using the weight-density of water of 62.4 lb/ft 3, we have the total force as We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. Its length is 10 / 3 ft and its height is 2.25 ft. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7. ![]()
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